The positive numbers 1, 2, 3... are known as natural numbers. The programs below takes a positive integer (let say n) as an input from the user and calculates the sum up to n.
Example #1: Sum of Natural Numbers Using for Loop
#include <stdio.h>
int main()
{
int n, i, sum = 0;
printf("Enter a positive integer: ");
scanf("%d",&n);
for(i=1; i <= n; ++i)
{
sum += i; // sum = sum+i;
}
printf("Sum = %d",sum);
return 0;
}
Example #2: Sum of Natural Numbers Using while Loop
#include <stdio.h>
int main()
{
int n, i, sum = 0;
printf("Enter a positive integer: ");
scanf("%d",&n);
i = 1;
while ( i <=n )
{
sum += i;
++i;
}
printf("Sum = %d",sum);
return 0;
}
Output
Enter a positive integer: 100
Sum = 5050
In both programs, the loop is iterated n number of times. And, in each iteration, the value of i is added to sum and i is incremented by 1.
Though both programs are technically correct, it is better to use for loop in this case. It's because the number of iteration is known.
The above programs doesn't work properly if the user enters a negative integer. Here's a little modification of the above program to take input from the user until positive integer is entered.
Example #3: Program to Read Input Until User Enters a Positive Integer
#include <stdio.h>
int main()
{
int n, i, sum = 0;
do {
printf("Enter a positive integer: ");
scanf("%d",&n);
}
while (n <= 0);
for(i=1; i <= n; ++i)
{
sum += i; // sum = sum+i;
}
printf("Sum = %d",sum);
return 0;
}
Visit this page to learn how to find the sum of natural number using recursion.
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