This program takes an arithmetic operator +, -, *, /
and two operands from the user and performs the calculation on the two operands depending upon the operator entered by the user.
Example: Simple Calculator using switch Statement
// Performs addition, subtraction, multiplication or division depending the input from user
# include <stdio.h>
int main() {
char operator;
double firstNumber,secondNumber;
printf("Enter an operator (+, -, *,): ");
scanf("%c", &operator);
printf("Enter two operands: ");
scanf("%lf %lf",&firstNumber, &secondNumber);
switch(operator)
{
case '+':
printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
break;
case '-':
printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);
break;
case '*':
printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
break;
case '/':
printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / firstNumber);
break;
// operator doesn't match any case constant (+, -, *, /)
default:
printf("Error! operator is not correct");
}
return 0;
}
Output
Enter an operator (+, -, *,): *
Enter two operands: 1.5
4.5
1.5 * 4.5 = 6.8
The *
operator entered by the user is stored in the operator variable. And, the two operands, 1.5 and 4.5 are stored in variables firstNumber and secondNumber respectively.
Since, the operator *
matches the case case '*':
, the control of the program jumps to
printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
This statement calculates the product and displays it on the screen.
Finally, the break
; statement ends the switch statement.
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