This program takes an arithmetic operator +, -, *, / and two operands from the user and performs the calculation on the two operands depending upon the operator entered by the user.
Example: Simple Calculator using switch Statement
// Performs addition, subtraction, multiplication or division depending the input from user
# include <stdio.h>
int main() {
    char operator;
    double firstNumber,secondNumber;
    printf("Enter an operator (+, -, *,): ");
    scanf("%c", &operator);
    printf("Enter two operands: ");
    scanf("%lf %lf",&firstNumber, &secondNumber);
    switch(operator)
    {
        case '+':
            printf("%.1lf + %.1lf = %.1lf",firstNumber, secondNumber, firstNumber + secondNumber);
            break;
        case '-':
            printf("%.1lf - %.1lf = %.1lf",firstNumber, secondNumber, firstNumber - secondNumber);
            break;
        case '*':
            printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
            break;
        case '/':
            printf("%.1lf / %.1lf = %.1lf",firstNumber, secondNumber, firstNumber / firstNumber);
            break;
        // operator doesn't match any case constant (+, -, *, /)
        default:
            printf("Error! operator is not correct");
    }
    
    return 0;
}
Output
Enter an operator (+, -, *,): *
Enter two operands: 1.5
4.5
1.5 * 4.5 = 6.8
The * operator entered by the user is stored in the operator variable. And, the two operands, 1.5 and 4.5 are stored in variables firstNumber and secondNumber respectively.
Since, the operator * matches the case case '*':, the control of the program jumps to
printf("%.1lf * %.1lf = %.1lf",firstNumber, secondNumber, firstNumber * secondNumber);
This statement calculates the product and displays it on the screen.
Finally, the break; statement ends the switch statement.
 
No comments:
Post a Comment